Solved] What is the value of [1 - tan(90° - θ) + sec(90&de
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What is the value of [1-tan(90-θ]²/[cos²(90- θ)]-1? (#SSCCGL Maths Questions)
![Solved] What is the value of [1 - tan(90° - θ) + sec(90&de](https://i.ytimg.com/vi/W28zDOHtfTQ/mqdefault.jpg)
cos(90−θ)sec(90−θ)tanθ/cosec (90−θ)sin(90−θ)cot(90−θ)+tan(90
![Solved] What is the value of [1 - tan(90° - θ) + sec(90&de](https://static.doubtnut.com/ss/web/2286754.webp)
1+tan^(2)(90^(@)-theta) का रूप secant के रूप में क्या होगा ?
![Solved] What is the value of [1 - tan(90° - θ) + sec(90&de](https://i.ytimg.com/vi/-ggOLvvhyt8/hqdefault.jpg?sqp=-oaymwEmCOADEOgC8quKqQMa8AEB-AH-BIAC4AOKAgwIABABGGEgYShhMA8=&rs=AOn4CLDw4_ud1JYg7dOQVQpDarKgiN4wWw)
Find the ratios for tan 90°, cosec 90°, sec 90° and cot 90°.
![Solved] What is the value of [1 - tan(90° - θ) + sec(90&de](https://toppr-doubts-media.s3.amazonaws.com/images/4358963/8c4fee7c-a77c-48e4-94ae-f1f7f8b51ae8.jpg)
33 Prove that ( frac { cot ( 90 - theta ) } { tan theta } + frac
![Solved] What is the value of [1 - tan(90° - θ) + sec(90&de](https://cdn1.byjus.com/wp-content/uploads/2022/04/Digital-BYJUS-Classes-Dino-popup.jpg)
Prove the following: tanθ +tan 90° θ =sec θ ·sec90° θ
![Solved] What is the value of [1 - tan(90° - θ) + sec(90&de](https://useruploads.socratic.org/DtUngKSI9312t44GB3QD_05BE1A90-244E-4236-8033-FA35E4F54F4A.jpeg)
How do you use csctheta=5 to find sec(90^circ-theta)?
![Solved] What is the value of [1 - tan(90° - θ) + sec(90&de](https://www.proprep.com/images/videos_thumbnails/5178.jpeg)
What is the value of tan 90?
![Solved] What is the value of [1 - tan(90° - θ) + sec(90&de](https://search-static.byjusweb.com/question-images/toppr_ext/questions/480308_454071_ans_3d40c02d934842a6a3ec0bcb9f2e2fff.png)
tan (90 - theta) is equivalent to cos thetasin theta(sin theta +
![Solved] What is the value of [1 - tan(90° - θ) + sec(90&de](https://ars.els-cdn.com/content/image/1-s2.0-S0048969721031636-gr5.jpg)
Toxicity and removal of parabens from water: A critical review - ScienceDirect
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Solved] In Δ ABC, ∠A = 90°, AD ⊥ BC at D. If
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