Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875
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![Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875](https://qph.cf2.quoracdn.net/main-thumb-246382234-100-xmnqeirzmhzuqzdmjyxpuehwegsqrhel.jpeg)
How can we prove Tan (90-theta) +cot (90-theta) =cosec (theta) *sec (theta)? - Quora
![Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875](https://i.ytimg.com/vi/s-qADItdenY/sddefault.jpg)
If `A+B=90` then prove that `sqrt((tanAtanB+tanAcotB)/(sinAsecB))=secA`
![Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875](https://toppr-doubts-media.s3.amazonaws.com/images/2888953/b7fb3889-3583-4805-9b99-e73792b88720.jpg)
a) (cosec ( A - sin A text { )(sec } A - cos A ) = frac { 1 } { tan A + cot A } )n(Hint - Simplify LHS and RHS separately
![Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875](https://i.ytimg.com/vi/yM05rvFLam0/maxresdefault.jpg)
If `A+B = 90^@`; prove that `sqrt((tanA tanB+tanA cotB)/(sinA secB) - (sin^2 B)/(cos^2A)) = tanA`
![Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875](https://i.ytimg.com/vi/LWAnlMBzi0o/maxresdefault.jpg)
Buktikan sec A. Tan(90⁰ -A)= csc A
![Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875](https://qph.cf2.quoracdn.net/main-thumb-252187817-200-yxedrlaqtluxydwvjmeuurmtouvxemph.jpeg)
How can we prove Tan (90-theta) +cot (90-theta) =cosec (theta) *sec (theta)? - Quora
![Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875](https://i.ytimg.com/vi/xGLPi62sGpY/hq720.jpg?sqp=-oaymwEhCK4FEIIDSFryq4qpAxMIARUAAAAAGAElAADIQj0AgKJD&rs=AOn4CLCe-EpvF16dzeCSZw1mhxjziIwRUA)
Tan (90- Ө) = Cot Ө and Cot (90- Ө) = Tan Ө
![Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875](https://i.ytimg.com/vi/1HNCepVoe0c/maxresdefault.jpg)
Q149, Prove that (secA-tanA)/(cosecA+cotA)=(cosecA-cotA)/(secA+tanA)
![Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875](https://hi-static.z-dn.net/files/da4/8deafa7a66ec0478b0702a465306eea8.jpg)
prove that cot(90-A)/tanA +cosec(90-A)sinA /tan(90-A)=sec (square )A
![Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875](https://i.ytimg.com/vi/P1LmYox-d3A/maxresdefault.jpg)
cotA + tanB)/(cotB + tanA) = cotAtanB Trigonometric Identity
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