Steps for the construction of a parallelogram ABCD with sides AB =4 cm and AD =5 cm and angle A =60∘ are given below.Choose the correct order.1. Construct a line segment AB =
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Steps for the construction of a parallelogram ABCD with sides AB =4 cm and AD =5 cm and angle A =60∘ are given below.Choose the correct order.1. Construct a line segment AB =4 cm and construct a 60∘ angle at point A.2. Mark the intersecting point as C. Join C to D and B to C.3. Draw an arc of radius 4 cm and D as centre to intersect the arc drawn in step 2 .4. Construct a line segment AD =5 cm on the other arm of the angle. Then draw an arc of radius 5 cm and B as centre. A. 1,4,3,2B. 1,2,3,4C. 1,3,2,4D. 1,4,2,3
Steps for the construction of a parallelogram ABCD with sides AB -4 cm and AD -5 cm and angle A -60- are given below-Choose the correct order-1- Construct a line segment AB -4 cm and construct a 60- angle at point A-2- Mark the intersecting point as C- Join C to D and B to C-3- Draw an arc of radius 4 cm and D as centre to intersect the arc drawn in step 2 -4- Construct a line segment AD -5 cm on the other arm of the angle- Then draw an arc of radius 5 cm and B as centre- A- 1-4-3-2B- 1-2-3-4C- 1-3-2-4D- 1-4-2-3
Steps for the construction of a parallelogram ABCD with sides AB -4 cm and AD -5 cm and angle A -60- are given below-Choose the correct order-1- Construct a line segment AB -4 cm and construct a 60- angle at point A-2- Mark the intersecting point as C- Join C to D and B to C-3- Draw an arc of radius 4 cm and D as centre to intersect the arc drawn in step 2 -4- Construct a line segment AD -5 cm on the other arm of the angle- Then draw an arc of radius 5 cm and B as centre- A- 1-4-3-2B- 1-2-3-4C- 1-3-2-4D- 1-4-2-3
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